Optimal. Leaf size=93 \[ -\frac {a^4 c^3 2^{m+\frac {9}{4}} (g \cos (e+f x))^{17/2} (\sin (e+f x)+1)^{-m-\frac {1}{4}} (a \sin (e+f x)+a)^{m-4} \, _2F_1\left (\frac {17}{4},-m-\frac {1}{4};\frac {21}{4};\frac {1}{2} (1-\sin (e+f x))\right )}{17 f g^7} \]
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Rubi [A] time = 0.28, antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {2840, 2689, 70, 69} \[ -\frac {a^4 c^3 2^{m+\frac {9}{4}} (g \cos (e+f x))^{17/2} (\sin (e+f x)+1)^{-m-\frac {1}{4}} (a \sin (e+f x)+a)^{m-4} \, _2F_1\left (\frac {17}{4},-m-\frac {1}{4};\frac {21}{4};\frac {1}{2} (1-\sin (e+f x))\right )}{17 f g^7} \]
Antiderivative was successfully verified.
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Rule 69
Rule 70
Rule 2689
Rule 2840
Rubi steps
\begin {align*} \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^3 \, dx &=\frac {\left (a^3 c^3\right ) \int (g \cos (e+f x))^{15/2} (a+a \sin (e+f x))^{-3+m} \, dx}{g^6}\\ &=\frac {\left (a^5 c^3 (g \cos (e+f x))^{17/2}\right ) \operatorname {Subst}\left (\int (a-a x)^{13/4} (a+a x)^{\frac {1}{4}+m} \, dx,x,\sin (e+f x)\right )}{f g^7 (a-a \sin (e+f x))^{17/4} (a+a \sin (e+f x))^{17/4}}\\ &=\frac {\left (2^{\frac {1}{4}+m} a^5 c^3 (g \cos (e+f x))^{17/2} (a+a \sin (e+f x))^{-4+m} \left (\frac {a+a \sin (e+f x)}{a}\right )^{-\frac {1}{4}-m}\right ) \operatorname {Subst}\left (\int \left (\frac {1}{2}+\frac {x}{2}\right )^{\frac {1}{4}+m} (a-a x)^{13/4} \, dx,x,\sin (e+f x)\right )}{f g^7 (a-a \sin (e+f x))^{17/4}}\\ &=-\frac {2^{\frac {9}{4}+m} a^4 c^3 (g \cos (e+f x))^{17/2} \, _2F_1\left (\frac {17}{4},-\frac {1}{4}-m;\frac {21}{4};\frac {1}{2} (1-\sin (e+f x))\right ) (1+\sin (e+f x))^{-\frac {1}{4}-m} (a+a \sin (e+f x))^{-4+m}}{17 f g^7}\\ \end {align*}
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Mathematica [F] time = 180.01, size = 0, normalized size = 0.00 \[ \text {\$Aborted} \]
Verification is Not applicable to the result.
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fricas [F] time = 0.51, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-{\left (3 \, c^{3} g \cos \left (f x + e\right )^{3} - 4 \, c^{3} g \cos \left (f x + e\right ) - {\left (c^{3} g \cos \left (f x + e\right )^{3} - 4 \, c^{3} g \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )\right )} \sqrt {g \cos \left (f x + e\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int -\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (c \sin \left (f x + e\right ) - c\right )}^{3} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 2.96, size = 0, normalized size = 0.00 \[ \int \left (g \cos \left (f x +e \right )\right )^{\frac {3}{2}} \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\int \left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (c \sin \left (f x + e\right ) - c\right )}^{3} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (g\,\cos \left (e+f\,x\right )\right )}^{3/2}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,{\left (c-c\,\sin \left (e+f\,x\right )\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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